Make the denominator into 10x:
5x/10x +20/10x=x(x+4)/10x
5x+20=x(x+4)
5x+20=x²+4x
x²-x-20=0
(x-5)(x+4)=0
x=5 or -4
the third choice is correct.
Not exactly sure which equation you meant:
3(100-b)=6b
300-3b=6b
300=9b
b= about 33
100-3b=6b
100=9b
b=about 11
Answer:
15 possible combinations
Step-by-step explanation:
Given
Required
Determine the possible number of combinations
The question emphasizes on "selection" which means "combination".
So; To answer this question, we apply the following combination formula:
In this case:
The formula becomes:
<em>Hence, there are 15 possible combinations</em>
Step-by-step explanation:
hopefully it is visible and makes sense
:)