2 years ago

Plz help I’m bad at math

Mathematics

1 answer:

Advocard [28]2 years ago

6 0

Answer:

1 is 136, 2 is 44, annd 4 is 44

Step-by-step explanation:

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I reallyy need help on this!<br> Thank you in advance

sattari [20]

Answer:828.96m^2

Step-by-step explanation:

radius(r)=8m

L=25m

π=3.14

total surface area of cone(tsa)=πxr^2+πxrxL

Tsa=3.14x8^2+3.14x8x25

Tsa=3.14x8x8+3.14x8x25

Tsa=200.96 + 628

Tsa=828.96

3 0

2 years ago

At Albemarle High School, 5/9 of the students are in band and 57% of the students are in chorus. Are more AHS students in band o

borishaifa [10]

Let find percentage of 5/9

$\\ \sf\longmapsto 5/9(100)$

$\\ \sf\longmapsto 500/9$

$\\ \sf\longmapsto 55.5\%$

More students are in chorus

8 0

2 years ago

Read 2 more answers

Alice wants to get enough tile to cover the kitchen and bathroom without appliances in them so they can use the extra for repair

Masteriza [31]

74 because if you count the full tiles u get 71

6 0

2 years ago

Read 2 more answers

In a game called Taxation and Evasion, a player rolls a pair of dice. If, on any turn, the sum is 7, 11, or 12, the player gets

AnnZ [28]

Answer:

$Probability = \frac{243}{1024}$

Step-by-step explanation:

Given

$Sum = \{7, 11, 12\}$

$Rolls = 5$

Required

Probability of not getting audited

If a pair of dice is rolled, the following are the observations of the sum

$Outcomes = 36$

$Sum\ of\ 7 = 6$

$Sum\ of\ 11 = 2$

$Sum\ of\ 12 = 1$

So, in a single roll; The probability of getting audited is:

$p= \frac{1 + 2 + 6}{36}$

$p= \frac{9}{36}$

$p= \frac{1}{4}$

The probability of not getting audited in a single roll is:

$q = 1 - p$ --- Complement rule

$q = 1 - \frac{1}{4}$

Take LCM

$q = \frac{4 - 1}{4}$

$q = \frac{3}{4}$

The probability of not getting audited in 5 rolls is:

$Probability = q^5$

$Probability = (\frac{3}{4})^5$

$Probability = \frac{3^5}{4^5}$

$Probability = \frac{243}{1024}$

7 0

2 years ago

The Widget Company is planning to produce widgets. The company has rented space for its manufacturing operation at $4,000 per mo

Helen [10]

I'll try to explain in the simplest way possible:

Total cost for a single widget: $32 + $44 = $76 for one widget.

So, since we know the cost of one widget is $76, then the price of 350 widgets would be = $76 x 350 = $26,600.

6 0

2 years ago