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2 years ago

What is the change in momentum of a 50. kg woman goes from running at 8.0 m/s to 0.0 m/s?

Physics

1 answer:

oksian1 [2.3K]2 years ago

4 0

Answer:

400 kg-m/s

Explanation:

Given that,

Mass of the woman, m = 50 kg

Initial velocity, u = 8 m/s

Final velocity, v = 0 m/s

We need to find the change in momentum of the woman. It can be given by :

$\Delta p=m(v-u)\\\\=50\times (8-0)\\\\=400\ kg-m/s$

So, the change in momentum is 400 kg-m/s.

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Answer:

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2 years ago

On a roller coaster ride at an amusement park, a car travels from 7.6 m/s to 56 m/s in 3 seconds. whats the cars acceleration?

nataly862011 [7]

Acceleration is defined as rate of change in velocity

So we can write its formula as

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2 years ago

A ship sinks in water when extra load is added to it why?

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Refer to attachment for your answer

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1 year ago

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A lead fishing weight of mass 0.20 kg is tied to a fishing line that is 0.50 m long. The weight is then whirled in a vertical ci

solong [7]

Answer:

Following are the solution to this question

Explanation:

please find the complete question in the attached file.

In point a:

The answer is "bottom".

In point b:

Using formula:

$T= mg + \frac{m V^2}{2}$

$\to 100= 0.2 \times 9.81 + \frac{0.2 \times V^2}{0.5}$

$\to 100= 1.962+ \frac{0.2 + V^2}{0.5}\\\\\to 100- 1.962= \frac{0.2 + V^2}{0.5}\\\\\to 98.038= \frac{0.2 + V^2}{0.5}\\\\\to 49.019=0.2+V^2\\\\\to 48.819=V^2\\\\ \to 6.987 \ \frac{m}{s}$

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2 years ago