Aye I need help on this rq plz

Area <br> help hellllppppp

slega [8]

Answer:

Area = 14¹/16 yd² or 14.0625 yd²

Step-by-step explanation:

2. The figure given is a square having equal sides of 3¾ yd each.

Formula for area of the square = a²

Where,

a = 3¾ yd

Plug in the value into the equation:

Area = (3¾)²

Change to improper fraction

Area = (15/4)²

Area = 225/16

Area = 14¹/16 yd² or 14.0625 yd²

8 0

2 years ago

F(x) =x2+2x-3 g(x)=3x-14

Leviafan [203]

The solution to the composite function f(g(x)) is 9x² - 78x + 165.

<h3>What is composite function?</h3>

A composite function is generally a function that is written inside another function.

Function composition is an operation that takes two functions f and g, and produces a function h = g ∘ f such that h(x) = g.

From the given composite function, the solution is determined as follows;

to solve for f(g(x)), we use the following methods.

f(x) = x² + 2x - 3, g(x) = 3x - 14

f(g(x)) = (3x - 14)² + 2(3x - 14) - 3

= 9x² - 84x + 196 + 6x - 28 - 3

= 9x² - 78x + 165

Thus, the solution to the composite function f(g(x)) is 9x² - 78x + 165.

Learn more about composite function here: brainly.com/question/10687170

#SPJ1

The complete question is below:

F(x) =x2+2x-3 g(x)=3x-14, find f(g(x))

8 0

9 months ago

Find the particular solution of the differential equation that satisfies the initial condition(s). f ''(x) = x−3/2, f '(4) = 1,

sweet [91]

Answer:

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

Step-by-step explanation:

This differential equation has separable variable and can be solved by integration. First derivative is now obtained:

$f'' = x - \frac{3}{2}$

$f' = \int {\left(x-\frac{3}{2}\right) } \, dx$

$f' = \int {x} \, dx -\frac{3}{2}\int \, dx$

$f' = \frac{1}{2}\cdot x^{2} - \frac{3}{2}\cdot x + C$ , where C is the integration constant.

The integration constant can be found by using the initial condition for the first derivative ( $f'(4) = 1$ ):

$1 = \frac{1}{2}\cdot 4^{2} - \frac{3}{2}\cdot (4) + C$

$C = 1 - \frac{1}{2}\cdot 4^{2} + \frac{3}{2}\cdot (4)$

$C = -1$

The first derivative is $y' = \frac{1}{2}\cdot x^{2}- \frac{3}{2}\cdot x - 1$ , and the particular solution is found by integrating one more time and using the initial condition ( $f(0) = 0$ ):

$y = \int {\left(\frac{1}{2}\cdot x^{2}-\frac{3}{2}\cdot x -1 \right)} \, dx$

$y = \frac{1}{2}\int {x^{2}} \, dx - \frac{3}{2}\int {x} \, dx - \int \, dx$

$y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x + C$

$C = 0 - \frac{1}{6}\cdot 0^{3} + \frac{3}{4}\cdot 0^{2} + 0$

$C = 0$

Hence, the particular solution of the differential equation is $y = \frac{1}{6} \cdot x^{3} - \frac{3}{4}\cdot x^{2} - x$ .

5 0

2 years ago

Please help me with this please

Reika [66]

9514 1404 393

Answer:

0

Step-by-step explanation:

The forces are equal and opposite, so the net force is zero.

5N -5N = 0

4 0

2 years ago

HELP PLEASE!!!!!!! Asap Giving out brainliest!<br> Which of the following has the greatest value?

Jlenok [28]

1/3^-2

You flip the denominator and the numerator to make the 3^-2 positive.

3^2/1= 3^2= 9

1/2^-3

2^3/1= 2^3= 8

I can already tell you that the negative exponents are not going to be as high in value.

3^-2= 1/3^2= 1/9
2^-3= 1/2^3= 1/8

1/3^-2 (the first option) <=== the highest in value

I hope this helps!
~kaikers

6 0

2 years ago