Dog weigh: 23
cat weigh: 5/8 dogs weigh
so..
23x5/8 = 115/8
Problema Solution
Terrance and Jesse are training for a long-distance race. Terrance trains at a rate of 6 miles every half hour, and Jesse trains at a rate of 2 miles every 15 minutes.
How long will each person take to run a total of 50 miles at the given rates?
Answer provided by our tutors
d = 50 mi the distance
t1 = the time of Terrance
t2 = the time of Jesse
Terrance trains at a rate of 6 miles every half hour thus his rate is:
v1 = 6/0.5 = 12 mph
Jesse trains at a rate of 2 miles every 15 minutes thus his rate is:
v2 = 2/(15/60) = 8 mph
since speed = distance/time follows time = distance/speed:
t1 = d/v1
t1 = 50/12
t1 = 4 1/6 hr
t1 = 4 hr 10 min
t2 = d/v2
t2 = 50/8
t2 = 6 1/4 hr
t2 = 6 hr 15 min
Terrance will run 4 hours and 10 minutes.
Jesse will run 6 hours and 15 minutes.
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In your question where ask to find the Standard Normal Distribution of the following:
give probabilities for 0<Z<infinity.
For these ranges, you can read directly, for example,
P(Z<1.96)=0.975.
So for #1, you read directly on the line 1.3 and column 0.03.
For #2, we note that the distribution is symmetrical about Z=0, so
P(Z<-2.33) is the same as P(Z>2.33)
which again is the same as
1-P(Z<2.33) because we know that the area under a probability distribution function adds up to 1.
For the remaining questions, work is similar to #2.