Answer:
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
Step-by-step explanation:
The sample proportion is p2= 7/27= 0.259
and q2= 0.74
The sample size = n= 27
The population proportion = p1= 0.4
q1= 0.6
We formulate the null and alternate hypotheses that the new program is effective
H0: p2> p1 vs Ha: p2 ≤ p1
The test statistic is
z= p2- p1/√ p1q1/n
z= 0.259-0.4/ √0.4*0.6/27
z= -0.141/0.09428
z= -1.496
The significance level ∝ is 0.05
The critical region for one tailed test is z ≤ ± 1.645
Since the calculated value of z= -1.496 does not fall in the critical region z < -1.645 we conclude that the new program is effective. We fail to reject the null hypothesis .
Y = 2
y = 4x - 10
2 = 4x - 10
2 + 10 = 4x
12 = 4x
12/4 = x
3 = x
solution is : (3,2)
Original:
<span>The width and length of a rectangle are consecutive odd integers
</span>so W = x and L = x + 2
<span>If the length is increased by 5 feet, then new L = x + 2 + 5 = x + 7
</span>
A = L x W
60 = (x + 7) x
60 = x^2 + 7x
x^2 + 7x - 60 = 0
(x - 5)(x + 12) = 0
x = 5 and x = -12
From here you have x = W = 5 ft and L = x + 2 = 5 + 2 = 7 feet
Area of original = 5 x 7 = 35
answer
<span>the area of the original rectangle: </span>35 ft^2
Assume the following:
Brad has been in the soccer team for b years.
Scot has been in the soccer team for s years.
"The number of years that brad has been on the soccer team is 2 less than 5 times the number of years that Scott has"
means: b=5s-2
"in total,the boys have been on the soccer team for 10 years."
means: b+s=10
so we have the equations:
i) b=5s-2
ii) b+s=10
substitute b in ii) with 5s-2, as they are equal, from i
(5s-2)+s=10
5s-2+s=10
6s=12
s=2,
then , from b+s=10, b=8
Answer: Brad has been in the team for 8 years.
Yes because
3 is x
And 5 is why so it’s
5 = 2 x 3 - 1
5= 6 -1
Which is 5