Fyi I didn't find this on google or anything I did the calculation on my computer and yes this is correct...
If it's wrong I'm sorry...
If it's wrong I'm sorry...
Please help me, will mark you brainly!!! Thank you if u do
1 answer:
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Answer:
a. True
b. True
c. False
d. False
Step-by-step explanation:
<u>First Table</u>
Length=10 feet, Width=4 feet
Area =10 X 4=40 Square Feet
<u>Second Table</u>
The second table is half as long as the first table.
Length =0.5 X 10 =5 feet
Area=5 X Width= 5w
The area of the second table is one fourth the area of the first table.
Area of Second Table = X Area of first table
5w= X 40
5w=10
Width of the Second table, w=2 feet
The following are true.
(a)The width of the second table is 2 feet.
(b) The area of the second table is 10 square feet.
The standard equation of a circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
(x-h)^2 + (y-k)^2 = r^2
where the center is at point (h,k)
From the statement of the problem, it is already established that h = 2 and k = -5. What we have to determine is the value of r. This could be calculated by calculating the distance between the center and point (-2,10). The formula would be
r = square root [(x1-x2)^2 + (y1-y2)^2)]
r = square root [(2--2)^2 + (-5-10)^2)]
r = square root (241)
r^2 = 241
Thus, the equation of the circle is
The figure on the top left is a triangle with base 11 and height 8, for an area of
Immediately below, we have a rectangle with dimensions 11 and 9, for an area of
Moving to the right, we have a parallelogram with base 9 and heght 11, which again has height
Finally, the rightmost figure is a triangle with base 8 and height 9, for a total of
Sum these areas and you'll get the total area