Answer:
The answer is B.
Step-by-step explanation:
The pattern seems to be counting by two.
Yes, to make it simpler and easier to tell, you could put both these fractions into decimals or percentages.
4/6 as a decimal would be .66 or 66%
4/7 as a decimal would be .57 or 57%
Hope this helps! :}
(D) traveled at the slowest rate.
Answer:
Step-by-step explanation:
Remark
The formula for this is
Heat = m * c * Δt
Givens
Heat = unknown
m = 200 grams
c = 4.184 Joules / grams oC
Δt = the change in temperature = 35.7 - 22.3 = 13.4
Solution
Heat = 200 * 4.184 * 13.4
Heat = 11213 Joules
Heat = 11.2 Kj
It's hard to get the correct number of sig digs because the 200 is not qualified in any way.
Part 2.
This can really puzzle you until you know that heat given up = the heat taken on. The heat taken on was 11.2 Kj. The Butane lighter must have given that heat on.
Heat of Combustion = Heat Given Up / Number grams burned.
Heat of Combustion = 11.2 Kj / 0.23 grams
Heat of Combustion = 48.8 Kj / gram
Answer:
Step-by-step explanation:
a)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,r =50
rate of change of area =dA/dt =2 pi *50 *25 =2500pi=7854
area growing 7854 cm2/s
b)area A=pi r^2
rate of change of area =dA/dt =2 pi r dr/dt
given dr/dt =25 ,A =64
pi r^2 =64
=>r =8/√pi
rate of change of area =dA/dt =2 pi *(8/√pi) *25 =400√pi=708.98
area growing 708.98 cm2/s
