Answer:
I think its b:/ srry if I'm wrong
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
512.50/125%=410
100% is the dealers cost
25% is the markup
$410 is the dealer's price before markup
410×25%=102.5. 410+102.5=512.5
3 3/4 - 2 1/3
get a common denominator of 12
3 3/4 * 3/3 = 3 9/12
2 1/3 * 4/4 = 2 4/12
3 9/12 - 2 4/12=
1 5/12
Answer: they ate 1 5/12 pints