1. 100 C
2. Point B to C is the ices heat capacity
3. During the points D to E the bonds of the water molecules build up enough kinetic energy to break their intermolecular bonds (not intra), which can lead to gas.
4. Between points D and E the energy is being released the energy required is equivalent along the line.
5. Between point E and D the water is converting to water (condensation)
6. Energy is being released 2260 j/g
7. Yes, but only under extreme volumetric pressures
8. D and E or B and C
9. Freezing (the water is also becoming less dense)
10. Melting or if water already, absorbtion of energy
11. released.
Answer:
301.8 g
Explanation:
We prepare a solution with 200.4 g of water (solvent) and 101.42 g of salt (solute). The mass of the solution is equal to the sum of the mass of the solvent and the mass of the solute.
m(solution) = m(solute) + m(solvent)
m(solution) = 200.4 g + 101.42 g
m(solution) = 301.8 g (we round-off to one decimal according to the significant figures rules)
Answer:
i) 0,7 molH20/s
ii)11,2 g O/s
iii)1,4 g H/s
Explanation:
i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):
ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):
iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):
Answer:
Widening of blood vessels.
Explanation:
The reduction of aldehydes, ketones, organic acids causes the formation of alcohols that is used for different process in the human body. This alcohol increase the width of the blood vessels as it enters the bloodstream causing greater flow of blood to the skin surface as well as temporary feeling of warmth. It also increased heat loss and rapid body temperature decrease that produces cooling effect in the body.
Answer:
Explanation:
The given reaction equation is:
2A + 4B → C + 3D
We know the mass of compound A in the reaction above. We are to find the mass of compound D.
We simply work from the known mass to calculate the mass of the unkown compound D
Using the mole concept, we can find the unknown mass.
Procedures
- We first find the molar mass of the compound A from the atomic units of the constituent elements.
- We then use the molar mass of A to calculate its number of moles using the expression below:
Number of moles of A =
- Using the known number of moles of A, we can work out the number of moles of D.
From the balanced equation of the reaction, it is shown that:
2 moles of compound A was used up to produced 3 moles of D
Then x number of moles of A would give the number of moles of D
- Now that we know the number of moles of D, we can find its mass using the expression below:
Mass of D = number of moles of D x molar mass of D