Find the area of the square, which has a side length of 2.
Area of square = 2 x 2 = 4
Now multiply the area by the length b
Volume = 4 x 5 = 20 square units total.
The objective function is simply a function that is meant to be maximized. Because this function is multivariable, we know that with the applied constraints, the value that maximizes this function must be on the boundary of the domain described by these constraints. If you view the attached image, the grey section highlighted section is the area on the domain of the function which meets all defined constraints. (It is all of the inequalities plotted over one another). Your job would thus be to determine which value on the boundary maximizes the value of the objective function. In this case, since any contribution from y reduces the value of the objective function, you will want to make this value as low as possible, and make x as high as possible. Within the boundaries of the constraints, this thus maximizes the function at x = 5, y = 0.
Um idk sorry lol that’s way to hard for me
Answer:
(A) 2^{5} * 5 * 7
Step-by-step explanation:
Your question formatting made it very complicated to understand the possible answers. Please use some notation or the equation editor next time.
So, the exponential form a way to write a number using multiplications and powers.
Let's examine the various options (if I read them correctly)
(A) 2^{5} * 5 * 7 - YES!
2^{5} is 32, so 32 * 5 * 7 = 160 * 7 = 1120
(B) 5² · 8 - NO
= 25 * 8 = 200
(C) 2² * 5³ * 7 - NO
= 4 * 125 * 7 =500 * 7 = 3500
(D) 2 · 5 · 7 - NO
= 10 * 7 = 70
Answer:
sound like a personal problem
Step-by-step explanation:
cuz