Total number of marble = 10
3green
2red
5 blue
Probability that the first marble is red = 2/10
Probability that the second is blue = 5/9(a reduction in the total number of marbles, because after the first marble was picked it wasn't replaced)
Probability of 1st and 2nd being red and blue respectively = 2/10 × 5/9
=1/9....
Hope this helped...?
the answer would be 3 I believe
Explicación paso a paso:
a+b=16 +
a-b=-4
----------
2a=12
a=6
b=10
el menor vale 6
<h2>y porfavor branliest! :)</h2>
<span>2x^2 + 3x + 5 = 0
a = 2 b = 3 and c = 5
x = [-b +-sq root(b^2 -4ac)] / 2a
</span><span>x = [-3 +-sq root(9 -4*2*5)] / 4
x = [-3 +-sq root(9 - 40)] / 4
</span><span>x = -(3 / 4) + sq root (-36) / 4
</span><span>x = -(3 / 4) - sq root (-36) / 4
</span>
Multiply everything in the parenthesis by 2.
2x + 3y + 2x - 2y - 3x
Combine like terms.
x + y
Hope this helps!
