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2 years ago

Help?............................

Mathematics

1 answer:

Yanka [14]2 years ago

4 0

Answer:

here you go, translated all points by looking and counting their distance to the x- and y-axis, then switched them and made one negative

but tldr: did it graphically.

the screenshot got the points you need

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How do you write two hundred and three thousandths in number form

maks197457 [2]

-- "Two hundred and three thousandths" means' ' 2.003 '.

-- "Two hundred three thousandths" would mean ' 0.203 '.

How can you tell the difference?

The difference is the 'and'. "And" means 'decimal point'.

' 678 ' is read as "six hundred seventy eight", with no 'and'.

' 40.06 ' is read as 'forty and six hundredths'.

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2 years ago

using the continuously compounding formula what would the balance be if you invest $5500 at a rate of 8% compunded continuously

vodomira [7]

The formula is A = Pe^(rt)
where A = amount in the account after a specified period of time
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2 years ago

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The diagram shows a circle with centre O. Points A , B, C and D all lie on the circumference of the circle.

kykrilka [37]

Answer:

The puck travels in a circular path of radius 0.25 m. ... C. away from the centre. D. ... If the speed of the mass at the top of the circle is 3.6

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1 year ago

Let events A and B and sample space S be defined as the following intervals: S = {x : 0 ≤ x ≤ 10} A = {x : 0 < x < 5} B =

iVinArrow [24]

The sample space of an event is the list of possible elements of the event.

The set elements are:

Ac = {x : 0, 5 ≤ x ≤ 10}
A n B = {x : 3 ≤ x ≤ 4}
A ∪ B = {x : 0 < x ≤ 7}
A∩Bc = {x : 1 ≤ x ≤ 2}
A^c ∪ B = {x : 0, 3 ≤ x ≤ 10}

<h3>How to determine the intervals of the subsets</h3>

The given parameters are:

S = {x : 0 ≤ x ≤ 10}

A = {x : 0 < x < 5}

B = {x : 3 ≤ x ≤ 7}

(a) Ac

This represents the list of elements in the universal set not in set A.

So, we have:

Ac = {x : 0, 5 ≤ x ≤ 10}

(b) A ∩ B

This represents the list of common elements in sets A and set B.

So, we have:

A n B = {x : 3 ≤ x ≤ 4}

(c) A ∪ B

This represents the list of all elements in sets A and set B, without repetition.

So, we have:

A ∪ B = {x : 0 < x ≤ 7}

d) A∩Bc

Given that:

B = {x : 3 ≤ x ≤ 7}

So, we start by calculating B^c i.e. the list of elements in the universal set not in set B.

So, we have:

Bc = {x : 1, 2, 8 ≤ x ≤ 10}

A∩Bc would then represent the list of common elements in sets A and set Bc

So, we have:

A∩Bc = {x : 1 ≤ x ≤ 2}

(e) A^c ∪ B

In (a), we have:

Ac = {x : 0, 5 ≤ x ≤ 10}

Given that:

B = {x : 3 ≤ x ≤ 7}

A^c ∪ B would then represent the list of all elements in sets Ac and set B

So, we have:

A^c ∪ B = {x : 0, 3 ≤ x ≤ 10}