Hi, so if x=0 and if y=x+5 then you would simply add 5 to x to get y, so in this case y=5. Then if x=1, then y would be 1+5, y=6. With the second part, it's the same thing. If x=1 and y=2x+3, all you have to do is multiply 1 by 2 wich = 2, then you would add 3 to that, wich is 5. And if x=2 and y=2x+3, then you would multiply 2 by 2, wich is 4, then add 3 to that wich would be 7.I hope this helps, respond to this answer if you have any comments or questions ;D
Answer:
x³ - 8x² - 11x + 148
Step-by-step explanation:
Given that x = 6 + i is a root then x = 6 - i is also a root
Complex roots occur as conjugate pairs.
The factors are therefore (x - (6 + i)) and(x - (6 - i))
Given x = - 4 is a root then (x + 4) is a factor
The polynomial is the product of the factors, that is
p(x) = (x + 4)(x - (6 + i))(x - (6 - i))
= (x + 4)(x - 6 - i)(x - 6 + i)
= (x + 4)((x - 6)² - i²)
= (x + 4)(x² - 12x + 36 + 1)
= (x + 4)(x² - 12x + 37) ← distribute
= x³ + 4x² - 12x² - 48x + 37x + 148
= x³ - 8x² - 11x + 148
Answer:
-6
Step-by-step explanation: