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2 years ago

The bionomial (x + 5) is a factor of x2 + 8x + 15. What is the other factor

Mathematics

2 answers:

Sliva [168]2 years ago

7 0

Answer:(x+3) is the other factor

Step-by-step explanation:

Dmitrij [34]2 years ago

7 0

Answer:

(x+3)

Step-by-step explanation:

x2+8x+15

(x+5)(x+3)

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Ok so you divide them and then make sure that 1 is the denominator and the numerator can be anything else

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2 years ago

a large water tank measures 6 feet across and 4 feet high. it is being filled with water at a rate of 10 gallons per minute. abo

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2 years ago

A library has 12,500 fiction books and 19,000 nonfiction books.

valentina_108 [34]

Answer:

1,260 books (or C)

Step-by-step explanation:

1. 2/5 of fiction (12,500) are out, so 5,000 are out

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7 0

2 years ago

Because of their connection with secant lines, tangents, and instantaneous rates, limits of the form ModifyingBelow lim With h

Gre4nikov [31]

Answer:

$\dfrac{1}{2\sqrt{x}}$

Step-by-step explanation:

$f(x) = \sqrt{x} = x^{\frac{1}{2}}$

$f(x+h) = \sqrt{x+h} = (x+h)^{\frac{1}{2}}$

We use binomial expansion for $(x+h)^{\frac{1}{2}}$

This can be rewritten as

$[x(1+\dfrac{h}{x})]^{\frac{1}{2}}$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}$

From the expansion

$(1+x)^n=1+nx+\dfrac{n(n-1)}{2!}+\ldots$

Setting $x=\dfrac{h}{x}$ and $n=\frac{1}{2}$ ,

$(1+\dfrac{h}{x})^{\frac{1}{2}}=1+(\dfrac{h}{x})(\dfrac{1}{2})+\dfrac{\frac{1}{2}(1-\frac{1}{2})}{2!}(\dfrac{h}{x})^2+\tldots$

$=1+\dfrac{h}{2x}-\dfrac{h^2}{8x^2}+\ldots$

Multiplying by $x^{\frac{1}{2}}$ ,

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}=x^{\frac{1}{2}}+\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}=\dfrac{h}{2x^{\frac{1}{2}}}-\dfrac{h^2}{8x^{\frac{3}{2}}}+\ldots$

$\dfrac{x^{\frac{1}{2}}(1+\dfrac{h}{x})^{\frac{1}{2}}-x^{\frac{1}{2}}}{h}=\dfrac{1}{2x^{\frac{1}{2}}}-\dfrac{h}{8x^{\frac{3}{2}}}+\ldots$

The limit of this as $h\to 0$ is

$\lim_{h\to0} \dfrac{f(x+h)-f(x)}{h}=\dfrac{1}{2x^{\frac{1}{2}}}=\dfrac{1}{2\sqrt{x}}$ (since all the other terms involve $h$ and vanish to 0.)

8 0

2 years ago

The answer to this................

pochemuha

Plot a point at the y-intercept of -2 or y = -2
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From there make a straight horizontal line
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Then Shade the upper-half of that line one color This shaded part stands for
Y > -2
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Shade the lower half a different color, this stands for y ≤ 6
-------------------------------------------------------------------------
That should be it!

3 0

3 years ago