Answer:
x = $200
The original price is $200
Question :
The price of a dress is reduced by 50%. When the dress still does not sell, it is reduced by 50% of the reduced price. If the price of the dress after both reductions is $50, what was the original price?
Step-by-step explanation:
Let x represent the original price of the dress.
First reduction
After first reduction the value of the price is given as;
p1 = x - 50% of x = (1-0.50)x = 0.5x
p1 = 0.5x
Second reduction
After the second reduction the value of the price is given as;
p2 = p1 - 50% of p1 = (1-0.50)p1 = (0.50)0.50x
p2 = 0.25x .....1
Since, p2 is given
p2 = $50
Substituting into equation 1
$50 = 0.25x
x = $50/0.25 = $200
x = $200
The original price is $200
I think the answer is 8x8 please dont judge me if it is wrong.
Answer:
23. x = 4; DE = 44
24. x = 25; DS = 28
Step-by-step explanation:
23. Point S is the midpoint of DE, so ...
DS = SE
3x +10 = 6x -2
12 = 3x . . . . . . . . . add 2-3x
4 = x . . . . . . . . . . . divide by 3
Then DS has length ...
DS = 3x +10 = 12 +10 = 22
and DE is twice that length, so ...
DE = 44
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24. DS is half the length of DE, so is ...
DS = DE/2 = 56/2
DS = 28
Then x can be found from ...
DS = x +3
28 -3 = x = 25 . . . . . substitute value for DS
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<em>Comment on problem 24</em>
Sometimes it is easier to work parts of a problem out of sequence. Here, finding DS first makes finding x easier.