Answer:
If `r` and `R` and the respective radii of the smaller and the bigger semi-circles then the area of the shaded portion in the given figure is: (FIGURE) `pir^2\ s qdotu n i t s` (b) `piR^2-pir^2\ s qdotu n i t s` (c) `piR^2+pir^2\ s qdotu n i t s` (d) `piR^2\ s qdotu n i t s`
Step-by-step explanation:
Step-by-step explanation:
A = -7.
B = -8 x-(-6) is the same as x + 6
C = 13
D = 2
E = -3
Answer: Choice 2) A, B, C
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Explanation:
Use a calculator to find that,
- 946/32 = 29.5625
- 1157/11 = 105.1818 approximately
- 3524/44 = 80.0909 approximately
- 37392/82 = 456
The first three results have a decimal portion as the answer. So there is a remainder here. The remainder is the leftover bit that couldn't make another full value. Only choice D results in a whole number that isn't a decimal value, so this does not have a remainder.
As a smaller example, let's say we had 20 cookies and 3 people. If we want to divide the cookies evenly, then each person gets 20/3 = 6 full cookies and there would be 2 cookies left over (6*3 = 18 are eaten so 20-18 = 2 is left over). Notice that 20/3 = 6.67 approximately. The non-whole number decimal value indicates we have a remainder. If we had 21 cookies, then each person gets 21/3 = 7 full cookies with nothing left over, so there's no remainder here.
Answer:
1/6
Step-by-step explanation:
1/4 = .25
2/3 = .6666...
.25(.6666...) = 1.6665...
1/6 = 1.666666
1/6 is the close enough answer bc the others would def not be it
1/3 = .3333....
3/7 = .428571428571
11/12 = 9.16666...
Hope this helps dude ! ^-^