Using the z-distribution, it is found that the lower bound of the 99% confidence interval is given by:
d. 68.39%.
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 99% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 2.575.
The sample size and estimate are given by:
Hence, the lower bound is given by:
Hence the lower bound is of 68.39%, which means that option D is correct.
More can be learned about the z-distribution at brainly.com/question/25890103
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Sum = 20(1-(1/4)^5) / (1-1/4) = 26.64
Answer:
step 1: x+50+4x=90
the angle of a right-angled triangle is 90 degrees, therefore if we add everything together ,we could work out what x is.
step 2: x+50+4x=90
x+4x=50
5x=50
x=10
then you solve the equation, x is 10
Answer:
Step-by-step explanation:
a) r = √(1² + (-5²)) = √26 = 5.09901...
θ = tan⁻¹(-5/1) = 4.9097... radians
(5.1, 4.9)
b) r = - 5.09901...
θ = 4.9097... - π = 1.76819...
(-5.1, 1.8)
Answer:
The probability that all the six people will test negative for the antibody is 0.9472.
The probability that the test comes back positive for at least one of the six people is 0.0528
Step-by-step explanation:
Consider the provided information.
probability that antibody is present will be effective is 99.1% and not present is 99.1% of the time.
Part (A)What is the probability that the test comes back negative for all six people?
Let P(X)= P(Antibody not present)
We want test comes back negative for all six that means antibody is present for all six. Thus X=0
The probability that all the six people will test negative for the antibody is 0.9472.
Part (B) What is the probability that the test comes back positive for at least one of the six people?
Hence, the probability that the test comes back positive for at least one of the six people is 0.0528
