Answer:
H0 : μN ≤ μD
H1 : μN > μD
Right tailed
Test statistic = 1.33
Pvalue = 0.097
Fail to reject the Null
Step-by-step explanation:
H0 : μN ≤ μD
H1 : μN > μD
The test is right tailed ; culled from the direction of the greater than sign ">"
Night students :
n1 =30 x1= 3.34 s1 = 0.02
Day students:
n2 = 30 x2 = 3.32 s2 = 0.08
The test statistic :
(x1 - x2) / √(s1²/n1) + (s2²/n2)
T= (3.34 - 3.32) / √(0.02²/30) + (0.08²/30)
T = 0.02 / 0.0150554
Test statistic = 1.328
Using the conservative approach ;
df = Smaller of n1 - 1 or n2 - 1
df = 30 - 1 = 29
Pvalue(1.328, 29) = 0.097
At α = 0.10
Pvalue < α ; Hence, we reject H0 ; and conclude that there is significant evidence that GPA of night student is greater than GPA of day student
Gcf = 7
42 + 35 = 7 x (6 + 5)
Answer:
Value of theta Ф = 1.33 radians
Step-by-step explanation:
We are given :
S= 8
r = 6
We need to find angle Ф
The formula used is: S=rФ
Finding theta Ф by putting values in formula:
So, value of theta Ф = 1.33 radians
22a+15c=228
a+c=11
a=11-c
22(11-c) + 15c = 228
242-22c + 15c = 228
-7c=-14
C = 2 (two children)
Remember how a + c = 11
a + 2 = 11
A= 9
9 adults, 2 children.
Answer:
your answer is c
Step-by-step explanation:
162 x .35 = 56.70
