Given:
The recipe calls for 
cup of strawberries for each gallon of lemonade.
Tia has 6 cups of strawberries.
To find:
The number of gallons of lemonade she can make.
Solution:
We have,
cup of strawberries for = 1 gallon of lemonade
cup of strawberries for = 
gallons of lemonade
= 
gallons of lemonade
= 
gallons of lemonade
cup of strawberries for = 
gallons of lemonade
= 
gallons of lemonade
= 
gallons of lemonade
Therefore, 9 gallons of lemonade she can make by using 6 cups of strawberries.
Answer:
51,111%
Step-by-step explanation:
We know that 45% have a dog but no cat. While 23% have both a dog and a cat.
Then Pr(X has cat|X has dog) = Pr(X has dog and cat)/Pr(X has dog)
= Pr(X has dog and cat)/Pr(X has dog) = 0.23/0.45 = 0.51 ≈ 51,111%
The probability that a student’s family owns a cat if the family owns a dog is 51,111%
2*7b =
use the distributive property
14b
46 and 19. 46 x 19 = 874 and 46 - 19 = 27
Answer:
Cos A = 24/25, Tan A = 7/25
Step-by-step explanation:
Given that Sin A = 7/25
Sin = Opp/hyp
Therefore using Pythagoras theorem, adjacent will be;
= √(25²-7²)
= √576
= 24
Thus;
Cos A = adjacent/hypotenuse
= 24/25
Cos A = 24/25
Tan A = opp/hypotenuse
= 7/25
Tan A = 7/25
