2 years ago

Would lengths of 15 inches, 10 inches and 6 inches form a triangle

Mathematics

1 answer:

Firdavs [7]2 years ago

8 0

Answer:

Yes

Step-by-step explanation:

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Which equation could have been used to create this graph?

andrew11 [14]

The answer is A hope this helps

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2 years ago

I have a few questions! a) x−1.27=4.09 b) 2.3−y=2.301 c) t+3.04=14.3 d) 1.1+k=5.67

maks197457 [2]

Answer:

a.) x = 5.36

b.) y = - 0.001

c.) t = 11.26

d.) k = 4.57

Step-by-step explanation:

a) x−1.27=4.09

b) 2.3−y=2.301

c) t+3.04=14.3

d) 1.1+k=5.67

Solving. right?

a.) x = 4.09 + 1.27 = 5.36

b.) y = 2.3 - 2.301 = - 0.001

c.) t = 14.3 - 3.04 = 11.26

d.) k = 5.67 - 1.1 = 4.57

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2 years ago

Find the value of X to the nearest tenth.

PIT_PIT [208]

Step-by-step explanation:

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1 year ago

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Write the ratio 2/5 Over 3/5 in simplest form.

ruslelena [56]

I think its 0.4 over 0.6

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2 years ago

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Use spherical coordinates. evaluate xyz dv e , where e lies between the spheres ρ = 4 and ρ = 6 and above the cone ϕ = π/3.

sergey [27]

Set

$x=\rho\cos\theta\sin\varphi$

$y=\rho\sin\theta\sin\varphi$

$z=\rho\cos\varphi$

so that the volume element is

$\mathrm dV=\mathrm dx\,\mathrm dy\,\mathrm dz=\rho^2\sin\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\varphi$

The integral is then

$\displaystyle\iiint_Exyz\,\mathrm dV=\int_{\varphi=0}^{\varphi=\pi/3}\int_{\theta=0}^{\theta=2\pi}\int_{\rho=4}^{\rho=6}\rho^5\cos\theta\sin\theta\sin^3\varphi\cos\varphi\,\mathrm d\rho\,\mathrm d\theta\,\mathrm d\rho$

$=\displaystyle\left(\int_0^{\pi/3}\sin^3\varphi\cos\varphi\,\mathrm d\varphi\right)\underbrace{\left(\int_0^{2\pi}\cos\theta\sin\theta\,\mathrm d\theta\right)}_0\left(\int_4^6\rho^5\,\mathrm d\rho\right)$

and so evaluates to 0.

3 0

2 years ago