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2 years ago

Write the equation for a line that intersects points (1,3) and (2,5)

Mathematics

2 answers:

Fiesta28 [93]2 years ago

7 0

Y=2x+1 is the correct answer

Georgia [21]2 years ago

3 0

Y=2x+1 is your answer

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5. Factor the expression: y2 + 6y – 16 a. (y – 8)(y + 2) b. (y + 8)(y – 2) c. (y + 4)(y + 4) d. (y + 4)(y – 4)

bagirrra123 [75]

y2+6y-16

(y+8)(y-2)

your answer is B

Hope this helps :)

3 0

2 years ago

Read 2 more answers

At her most recent race, Sue finished in 272 minutes. That is 15% less time than the previous race. What was her time in the pre

ValentinkaMS [17]

Answer:

320 minutes was her time on the previous race

Step-by-step explanation:

Let the time spent on the previous race be x minutes.

Given that at her most recent race, Sue finished in 272 minutes which is 15% less time than the previous race then

x - 15% * x = 272

x - 0.15x = 272

0.85x = 272

x = 272/0.85

x = 320 minutes

7 0

2 years ago

Judy jarred 45 liters of jam after 9 days. How much jam did Judy jar if she spent 10 days making jam? Assume the relationship is

nikitadnepr [17]

50 liters i’m sure. you didn’t give an exact pattern

6 0

2 years ago

Find the number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4. Hint consider the

Verdich [7]

Answer:

1364 is the number of possibilities for positive integers less than 1,00,000.

Step-by-step explanation:

1. 5 digit numbers:

We have 5 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 5 digit numbers:

$4 \times 4 \times 4 \times 4 \times 4\\ \Rightarrow 1024$

2. 4 digit numbers:

We have 4 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 4 digit numbers:

$4 \times 4 \times 4 \times 4 \\ \Rightarrow 256$

3. 3 digit numbers:

We have 3 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 3 digit numbers:

$4 \times 4 \times 4 \\ \Rightarrow 64$

4. 2 digit numbers:

We have 2 places here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 2 digit numbers:

$4 \times 4 \\ \Rightarrow 16$

5. 1 digit numbers:

We have 1 place here, and each place can have 4 options because repetition is allowed.

So, total number of possibilities for 1 digit numbers:

$4$

We can add all the above possibilities to find the total.

So, number of positive integers less than 100,000 whose digits are among 1, 2, 3, and 4 = 1024 + 256 + 64 + 16 + 4 = 1364

3 0

2 years ago

Help Please I will give brianliest if correct!!

Tomtit [17]

A student has $78 in his checking account. If the student spends $12 on lunch, which number could be combined with the amount left in the account to make zero?

–90

–78

–66

–12

8 0

2 years ago

Read 2 more answers