PLZ HELPP ASAPPP ITS DUE SOOOOON

Prove that : cos10° - sin10° / sin10° + cos10° = tan35°

Digiron [165]

Step-by-step explanation:

(cos 10° − sin 10°) / (cos 10° + sin 10°)

Rewrite 10° as 45° − 35°.

(cos(45° − 35°) − sin(45° − 35°)) / (cos(45° − 35°) + sin(45° − 35°))

Use angle difference formulas.

(cos 45° cos 35° + sin 45° sin 35° − sin 45° cos 35° + cos 45° sin 35°) / (cos 45° cos 35° + sin 45° sin 35° + sin 45° cos 35° − cos 45° sin 35°)

sin 45° = cos 45°, so dividing:

(cos 35° + sin 35° − cos 35° + sin 35°) / (cos 35° + sin 35° + cos 35° − sin 35°)

Combining like terms:

(2 sin 35°) / (2 cos 35°)

Dividing:

tan 35°

3 0

2 years ago

I need help on thi and the first person who answer correctly gets a BRANLIST and show work

const2013 [10]

Answer:

w<6 THE SMALL LINE UNDER THE LESS THAN SIGN IS STILL THERE I JUST CANNOT ADD IT

Step-by-step explanation:

first solve the equation to the right.

-3(2w+1) = -6w-3

now solve the whole equation

-33-w< -6w-3

-w+6w < -3+33

5w < 30

divide the 5 from both sides to simplify

5/5w < 30/5

w < 6

THE ANSWER IS w < 6

3 0

2 years ago

A box of Munchkins contains chocolate and glazed donut holes. If Jacob ate 2 chocolate

neonofarm [45]

Answer:

24 munchkins.

Step-by-step explanation:

Let C be the number of chocolate and D be number of glazed donut holes in the original box.

We are told if Jacob ate 2 chocolate munchkins, then 1/11 of the remaining Munchkins would be chocolate. We can represent this information as:

$C-2=\frac{1}{11}*(C+D-2)...(1)$

We are also told if he instead added 4 glazed Munchkins to the original box, 1/7 of the Munchkins would be chocolate. We can represent this information as:

$C=\frac{1}{7}*(C+D+4)...(2)$

Upon substituting C's value from equation (2) in equation (1) we will get,

$\frac{1}{7}*(C+D+4)-2=\frac{1}{11}*(C+D-2)$

Let us have a common denominator on right side of equation.

$\frac{1}{7}*(C+D+4)-\frac{7*2}{7}=\frac{1}{11}*(C+D-2)$

$\frac{C+D+4-14}{7}=\frac{1}{11}*(C+D-2)$

Multiplying both sides of our equation by 7, we will get,

$7*\frac{C+D-10}{7}=7*\frac{1}{11}*(C+D-2)$

$C+D-10=\frac{7}{11}*(C+D-2)$

Multiplying both sides of our equation by 11, we will get,

$11*(C+D-10)=11*\frac{7}{11}*(C+D-2)$

$11*(C+D-10)=7*(C+D-2)$

$11C+11D-110=7C+7D-14$

$11C-7C+11D-7D=-14+110$

$4C+4D=96$

$4(C+D)=96$

$(C+D)=\frac{96}{4}$

$(C+D)=24$

Therefore, the total number of Munchkins in original box is 24.

3 0

2 years ago

A school is arranging a field trip to the zoo. The school spends 635.85 dollars on passes for 43 students and 2 teachers. The sc

aalyn [17]

Answer:

$22.67

Step-by-step explanation:

The school spends 635.85 dollars on passes for 43 students and 2 teachers, then the school spends

$\$635.85 :(43+2)=\$14.13$ per person.

The school also spends 367.22 dollars on lunch for just the students, so the school spends

$\$367.22 :43=\$8.54$ per person.

In total, a pass and lunch for each student was spent

$\$14.13+\$8.54=\$22.67$

7 0

2 years ago

Which of the following equations describes the graph?

cluponka [151]

Answer:

Which cone has a volume of 24 7 cm?

-

1

-

3.5 cm!

4.5 cm

1

6.5 cm

B = 25.4 cm

1

7/5 cmi

1

8 cm

3 cm

B = 42

Step-by-step explanation:

3 0

2 years ago