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2 years ago

Find the missing side length.

Mathematics

1 answer:

andrew11 [14]2 years ago

5 0

So first of all you know that one side is 14cm and the other side is 6cm

What you would do is: 14-6=???

Your answer should be: 8cm

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Ben plays basketball 6 times every 3 weeks. At this rate how many times does he play basketball in 10 weeks ?

Dimas [21]

Ben will play 18times

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1 year ago

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Does anyone know #11

lara31 [8.8K]

Answer:

C. both student 1 and student 2

Step-by-step explanation:

Dilation does not change any angles, so the triangles are similar and the trig functions of corresponding angles will be identical.

The slope of CB is -1/3 and the slope of BA is 3, so they multiply together to give -1. That means the segments are at right angles and the triangle is a right triangle.

Both the premise and the conclusion of each student is correct.

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2 years ago

How long can I talk on the phone if they charge 8 cent a minute and I have 90 cents

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2 years ago

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Realice la óperacion y exprese el resultado en notación científica (0,00000826) (235×10 elevado a -7) sobre 0,0017×10 elevado a

earnstyle [38]

Answer:

1,42 * 10 ^ -5

Step-by-step explanation:

La notación científica también se conoce como forma estándar.

Tenemos que realizar la siguiente operación y dejar el resultado en forma estándar.

Entonces;

0,00000826 * 235 × 10 ^ -7 / 0,0017 × 10 ^ -2

También;

8.26 * 10 ^ -6 * 2.35 * 10 ^ -5 / 1.7 * 10 ^ -5

= 19,411 * 10 ^ -11 / 1,7 * 10 ^ -5

= 1,42 * 10 ^ -5

6 0

2 years ago

How do you solve these equations? I don't want you to answer all of them, just tell me how to solve each type of equation on the

miss Akunina [59]

Answer:

8. Identify the common denominator; express each fraction using that denominator; combine the numerators of those rewritten fractions and express the result over the common denominator. Factor out any common factors from numerator and denominator in your result. (It's exactly the same set of instructions that apply for completely numerical fractions.)

9. As with numerical fractions, multiply the numerator by the inverse of the denominator; cancel common factors from numerator and denominator.

10. The method often recommended is to multiply the equation by a common denominator to eliminate the fractions. Then solve in the usual way. Check all answers. If one of the answers makes your multiplier (common denominator) be zero, it is extraneous. (10a cannot have extraneous solutions; 10b might)

Step-by-step explanation:

For a couple of these, it is helpful to remember that (a-b) = -(b-a).

$\dfrac{5}{x+2}+\dfrac{25-x}{x^2-3x-10}=\dfrac{5(x-5)}{(x+2)(x-5)}+\dfrac{25-x}{(x+2)(x-5)}\\\\=\dfrac{5x-25+25-x}{(x+2)(x-5)}=\dfrac{4x}{x^2-3x-10}$

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$\displaystyle\frac{\left(\frac{x}{x-2}\right)}{\left(\frac{2x}{2-x}\right)}=\frac{x}{x-2}\cdot\frac{-(x-2)}{2x}=\frac{-x(x-2)}{2x(x-2)}=-\frac{1}{2}$

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$\dfrac{3}{x-1}+\dfrac{6}{x^2-3x+2}=2\\\\\dfrac{3(x-2)}{(x-1)(x-2)}+\dfrac{6}{(x-1)(x-2)}=\dfrac{2(x-1)(x-2)}{(x-1)(x-2)}\\\\3x-6+6=2(x^2-3x+2) \qquad\text{multiply by the denominator}\\\\2x^2-9x+4=0 \qquad\text{subtract 3x}\\\\(2x-1)(x-4)=0 \qquad\text{factor; x=1/2, x=4}$

Neither solution makes any denominator be zero, so both are good solutions.

8 0

2 years ago