Solve your system of equations.
2x+y=1;4x+2y=−1
Solve 2x+y=1 for y:
2x+y+−2x=1+−2x(Add -2x to both sides)
y=−2x+1
Substitute (−2x+1) for y in 4x+2y=−1:
4x+2y=−1
4x+2(−2x+1)=−1
2=−1(Simplify both sides of the equation)
2+−2=−1+−2(Add -2 to both sides)
0=−3
Answer: No solution. C)
Answer:
it should be 12
Step-by-step explanation:
because 3x4=12
Answer:
y=mc
Step-by-step explanation:
Answer:
Step-by-step explanation:
Given Equation:
Equation:1
Equation:2
Dividing Equation:2 by '3' both the sides:
or Equation:3
Putting the vale of 'x' in Equation:1
Subtracting '3' both sides
Putting value of 'y' in Equation:3
The solution of the equations is :
Middle option.
<span>(x + 1 ≤ 1) ∩ (x + 1 ≥ 1)
If you work both sides separately you get
</span>(x ≤ 0) ∩ (x ≥ 0)
<span>
which reduces nicely to
</span><span>{x | x = 0}</span>