A leftward force of 7N is applied to a box while the force of friction is 3N. The weight of the box is 4N as is the normal force
1 answer:
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Answer:
70.07 Hz
Explanation:
Since the sound is moving away from the observer then
and
when moving towards observer
With of 76 then taking speed in air as 343 m/s we have
Similarly, with of 65 we have
Now
v_s=27.76 m/s
Substituting the above into any of the first two equations then we obtain
Explanation:
Formula to represent thrust is as follows.
F =
=
or, p =
F =
=
= 201.67 N
Thus, we can conclude that the thrust is 201.67 N.