3.78/6= 0.63
$0.63 per bottle
42(0.63)= $26.46
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Method 1
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Since the numerators are the same, the smaller the denominators, the greater the fraction is.
Arranging from the least to the greatest
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Method 2
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Lets change all to the same denominators
Now that all the denominators are the same, we can arrange the fractions by comparing the numerators. The bigger the numerators, the greater the fraction.
Arranging from the least to the greatest
<h3>
Answer: There is only one answer and it is choice B</h3><h3>Angle 1 and angle 4 are alternate interior angles</h3>
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Explanation
- A. This is false because it should be angle 4 + angle 5 = 180 without the angle 6. Adding on angle 6 results in some angle larger than 180. Note how angle 5 = (angle 3)+(angle 6).
- B. This is true and useful to showing that the three angles of a triangle add to 180 degrees. This is because you'll use the fact that angles 4, 5 and 6 combine to 180 degrees.
- C. While this is a true statement by the exterior angle theorem, it is not useful to the proof. It is better to state that angle 2 and angle 6 are congruent because they are alternate interior angles.
- D. Like choice C, it is true but not useful. It's better to say that angle 1 is congruent to angle 4. See choice B above.
Note how it's not enough for a statement to be true. It also needs to be relevant or useful to the context at hand. A more simpler example of this could be stating that x+x = 2x.
Can you give the data please?
Answer:
<em />
- <em>It takes</em><u> 2.5 minutes </u><em>to fill the tank.</em>
Explanation:
The net speed or net rate for filling the 10-liters tank is equal to the speed the tap is filling less the speed the water is leaking through the hole located at the bottom of the tank:
- Net rate = rate of filling - rate of leaking
- Net rate = 5 liters/minute - 1 liter/minute
- Net rate = 4 liters/minute
Thus, consiedering the tank is empty at the beginning, the time is:
- Time = Volume of the tank / net rate of filling
- Time = 10 liters / (4liters/minute)
- Time = 2.5 minutes ← answer