For a function (fn) to be odd:
f(x) = - f(-x)
For a fn to be even:
f(x) = f(-x)
For a fn to be neither even nor odd
f(x) != f(-x) [No Relation]
(-x)^n = x^n for n -> even
(-x)^n = -x^n for n -> odd
In your example:
f(x) = -4x^3 + 4x
f(-x) = -4 (-x)^3 + 4 (-x)^1 ( 3 and 1 are odd powers )
f(-x) = 4x^3 - 4x (take -1 common to do the check)
f(-x) = -( -4x^3 + 4x ) = - f(x) [between the bracket was the original fn]
f(x) = - f(-x)
so the function is odd also called symmetric about the origin
Answer:
4 - 3j
Step-by-step explanation:
Hello XD
3(x+2) = 3x+6
Distributive property
(3)(x)+(3)(2) = 3x+6
3x+ 6 = 3x+6
Now subtract 3x from both sides
3x+6-3x = 3x+6-3x
6=6
Subtract 6 from both sides
6-6 = 6-6
0=0
In this case the answer is : All real numbers are solution
When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of <u>
pemdas</u>
and to make sure that we take each step carefully.
We first would <u>
</u>
<u>
(first)</u>
simplify the following:
Plug the x in :)
3(2) + 8
6 + 8
=14