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2 answers:
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Actually Welcome to the Concept of the volumes.
Here given as, r= 6.2 mm, h = 10.8 mm, π=3.14
hence, the volume of the cone is
Volume = 1/3(πr^2h)
===> vol = 1/3(3.14*(6.2)^2*(10.8))
==> Vol = 1/3*(1303.57)
==> Vol = 434.52 mm^3
Hence the volume of the cone is 434.52 mm^3
For this case we have the following functions:
When x = 0 we have:
For y1:
For y2:
Therefore, we have to:
When x = 5 we have:
For y2:
For y3:
Therefore, we have to:
When x = -1 we have:
For y1:
For y2:
For y3:
Therefore, we have to:
Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2
When x = 0 we have:
For y1:
For y2:
Therefore, we have to:
When x = 5 we have:
For y2:
For y3:
Therefore, we have to:
When x = -1 we have:
For y1:
For y2:
For y3:
Therefore, we have to:
Answer:
When x = 0, y1 = y2
When x = 5, y2 <y3
When x = -1, y3 <y1 <y2