The picture in the attached figure
we know that
If line GJ bisects the angle FGH, that means we also know that the angle FGH is divided into two equal sizes.
Now, we have
Angle FGJ = Angle HGJ
Angle GJF = Angle GJH
This information means that angle GHJ = angle GFJ
We have two congruent right-angled triangle
We can then further deduce that
Side GF = Side GH
Since triangle FGJ and triangle GJH are congruent,
then
side FJ equals to side JH
3x-8=16
3x=16+8
3x=24
x=8 units
Hence,
the length of FH = 2×8=16 units
the answer isFH=16 units
Ok <span>One side would have a length of 4, another side would have a length of 5, and then we can use the Pythagorean Theorem to find the length of the hypotenuse. a^2 + b^2 = c^2 </span>
<span>a=4; b=5; </span>
<span>4^2 + 5^2 = c^2 </span>
<span>16 + 25 = c^2 </span>
<span>41 = c^2 </span>
<span>c = √41 </span>
<span>Therefore, the hypotenuse has a length of √41. </span>
<span>To find the sinθ, you take the opposite over the hypotenuse. </span>
<span>Remember when you drew out the triangle? θ is the angle connected to the origin. The opposite side is b, which is 5. </span>
<span>Your answer is 5/√41. </span>
<span>This answer must be simplified since there is a radical in the denominator. To simplify, you can just multiply the numerator and the denominator by √41/√41 (since this is equivalent to 1). </span>
<span>This gives you the answer
</span>
There is no solution to this problem
The answer is: "12 feet" .
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Note: In a square, the length of EACH of the four sides of the square is the same.
Area = Length * width.
For a square, length = width.
So for a square, Area = length * width = (length of a side)² = s² ,
Given: A = s² = 144 ft² ;
Solve for the positive value of "s" .
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→ s² = 144 ft² ; Take the "square root" of each side ;
→ √(s²) = √(144 ft²) ;
→ s = 12 ft.
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The answer is: 12 ft.
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Answer:
x = -1 and y = -1
Step-by-step explanation:
to solve this equation we say
let
2x-5y=3.......................................... equation 1
4y-x=-3............................................equation 2
from equation 2
4y-x=-3............................................equation 2
4y + 3 = x
i.e
x = 4y + 3 ............................................. equation 3
put x = 4y + 3 in equation 1
2(4y +3) - 5y = 3
8y + 6 -5y = 3
3y +6 = 3
3y= 3-6
3y -3
divide both sides by the coefficient of y which is 3
3y/3 = -3/3
y = -1
put y = -1 into equation 3
x = 4y + 3 ............................................. equation 3
x = 4(-1) + 3
x = -4 + 3
x = -1
therefore the value of x = -1 and y = -1 respectively