Answer:
The distance between B and lighthouse is 3.8688 km
Step-by-step explanation:
Given:
The angle made from ship to lighthouse is 36.5 degrees
and that of point B is 73 degrees.
To Find:
Distance Between Point B and Lighthouse
Solution:
<em>Consider a triangle LAB(Refer the attachment )</em>
And Point C is on the line AB as A i.e. ship is sailing to B
So C is at 5 km from A.
Now In triangle LAC,
Using Trigonometry Functions as ,
tan(36.5)=LC/AC
LC=tan(36.5)*AC
=0.7399*5
=3.6998 km
Now In triangle LBC,
As,
Sin(73)=LC/LB
LB=LC/(Sin(73))
=3.6998/0.9563
=3.8688 km
LB=3.8688 km
B. -9 is the most negative one, -2 is the least.
Hope this helps you.
Answer:
Positive 3
Step-by-step explanation:
you have to add 4 and -9 first and you get -5 then you add that to positive 8 and get 3
Using proportions, it is found that Ermias is traveling at a rate of 11 mph and Jeremiah at a rate of 19 mph.
<h3>What is a proportion?</h3>
A proportion is a fraction of a total amount, and the measures are related using a rule of three.
Jeremiah travels 8 mph faster than Ermias, hence their velocities are:
x, x + 8
They travel in opposite directions, hence in one hour they are 2x + 8 apart.
In eight hours, the distance is 8(2x + 8), which is of 240 miles, hence:
8(2x +8) = 240
2x + 8 = 30
2x = 22
x = 11.
Then:
- x = 11 + 8 = 19 -> Jeremiah.
More can be learned about proportions at brainly.com/question/24372153
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