Answer:
11). 
= 90°
12). 
= 212°
Step-by-step explanation:
A circle F with AB and CD are the diameters has been given in the figure attached.
11). Since, 
= 180°
and 
Therefore, 
= 180°
32° + + 58° = 180°
= 180° - 90°
= 90°
12. Since, 
= 32°
= 
= 180° + 32°
= 212°
Answer:
Let's define the high temperature as T.
We know that:
"four times T, was more than 2*T plus 66°C"
(i assume that the temperature is in °C)
We can write this inequality as:
4*T > 2*T + 66°C
Now we just need to solve this for T.
subtracting 2*T in both sides, we get:
4*T - 2*T > 2*T + 66°C - 2*T
2*T > 66°C
Now we can divide both sides by 2:
2*T/2 > 66°C/2
T > 33°C
So T was larger than 33°C
Notice that T = 33°C is not a solution of the inequality, then we should use the symbol ( for the set notation.
Then the range of possible temperatures is:
(33°C, ...)
Where we do not have an upper limit, so we could write this as:
(33°C, ∞°C)
(ignoring the fact that ∞°C is something impossible because it means infinite energy, but for the given problem it works)
Answer:
3000
Step-by-step explanation:
a decrease in the ratio 5:3 implies that:
new quantity :old quantity :5:3
let new quantity be x.
x:1800=5:3
x/1800=5/3
3x=9000
x=9000/3
x=3000
Refer to the figure shown below.
The coordinates of point m are (2,5).
Let (x,y) = the coordinates of pont n.
Because mn = 4, use the Pythagorean theorem to obtain
(x - 2)² + (y - 5)² = 4²
This represents a circle with center at (2,5) and radus = 4.
Answer:
Possible coordinates for n lie on the circle (x-2)² + (y-5)² = 16.
