A right triangle's longest side is the hypotenuse
let x=longest, y=middle, and z=shortest
x=y+2
y=2z-1
therefore x=(2z-1)+2=2z+1
find z
z^2+y^2=x^2 by Pythagorean theorem
plug in x and y in terms of z
z^2+(2z-1)^2=(2z+1)^2
z^2+4z^2-4z+1=4z^2+4z+1
subtract the right-hand side's value from the left-hand side's
z^2-8z=0
z(z-8)=0
z=0, 8
z cannot be zero as the sides must have some value to it.
Therefore the shortest side is equal to 8
Answer:
0.99
Step-by-step explanation:
.33 x .75 = .2475 or 0.99/4
Answer:
x = 5
Step-by-step explanation:
25 = 6x - 5 (add 5 on both sides)
+5 +5
30 = 6x (divide by 6 on both sides)
5 = x
Hope this helps ya!!
Add the bases together, divide that by 2 then multiply by the height.
15.8 + 21.8 = 37.6
37.6/2 = 18.8
18.8 x 11.7 = 219.96 yd^2
Answer:
can you show the other answers to see if I have the answer sorry.
