This must be on the moon as the acceleration due to gravity in this equation must be around 1/8 that on earth. :) Anyway...
h=-2t^2+9t+11
A)
dh/dt=-4t+9, when velocity, dh/dt=0, it is the maximum height reached
dh/dt=0 only when 4t=9, t=2.25 seconds
h(2.25)=21.125 ft (21 1/8 ft)
B)
As seen in A), the time of maximum height was 2.25 seconds after the squirrel jumped.
C)
The squirrel reaches the ground when h=0...
0=-2t^2+9t+11
-2t^2-2t+11t+11=0
-2t(t+1)+11(t+1)=0
(-2t+11)(t+1)=0, since t>0 for this problem...
-2t+11=0
-2t=-11
t=5.5 seconds.
To subtract? as minus means subract/take away?
Answer:
x=7
Step-by-step explanation:
since it is the same side length,
3x+6 = 10x-43
3x-10x = -43-6
-7x = -49
x=-49/-7=7
please mark brainliest
Answer:
x≥5
Step-by-step explanation:
-1 ≥ x/-5
x/-5 ≤ -1
x(-1)/5 ≥ (-1) (-1)
x/5 ≥ 1
5x/5 ≥ 1 ×5
x ≥ 5
I'm not sure but I tried.
For the graph: you can draw a line about 15cm, put 0 at the start then after 5cm put 5 then 10 at 10cm and 15 at the end. At 5 put • that's the starting and go all the way to 15 and add > to show that the line continues. I'm not good at explaining but I hope it helps.
