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2 years ago

PLZ HELP ME What shape is this cross-section?

Mathematics

1 answer:

Irina18 [472]2 years ago

6 0

Answer:

i'm not sure if i'm right but think is cube

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What is "a" in the question?

Sergeeva-Olga [200]

Answer:

a=2.4

Step-by-step explanation:

4 0

2 years ago

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Evaluate the following functions for the given value.<br> 19. f(x) = -x3 + x2; -2

suter [353]

Answer:

Step-by-step explanation:

f(x) = -x^3 + x^2

Let x = -2

Evaluate the expression

f(-2) = -(-2)^3 + (-2)^2

= - (-2)*(-2) * (-2) + ( -2) * (-2)

= -(-8) + ( 4)

= 8 + 4

= 12

3 0

1 year ago

Add and Subtract Rational Expressions with a Common Denominator

Sladkaya [172]

Answer:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}$

Step-by-step explanation:

<u>Simplifying Rational Expressions</u>

If two or more rational expressions have the same denominator, the add and subtract operations are done only with the numerator. The final denominator will be the common of both.

The expression is:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}$

Operating on the numerators:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-(3q^2-q-6)}{q^2+6q+5}$

Removing parentheses:

$\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{4q^2-q+3-3q^2+q+6}{q^2+6q+5}$

Simplifying:

$\boxed{\displaystyle \frac{4q^2-q+3}{q^2+6q+5}-\frac{3q^2-q-6}{q^2+6q+5}=\frac{q^2+9}{q^2+6q+5}}$

The expression cannot be further simplified.

7 0

2 years ago

M plus three n equals 1 for n

sineoko [7]

You use 1 step equation to find out the answer

8 0

2 years ago

Look at the photo pick A B C D either one explanation not needed thank you! <3

emmainna [20.7K]

Answer:

Step-by-step explanation:

-5 i s greater than -2.

Nope that aint true

-2 is greater than -5 is correct since -2 is closer to the postivie numbers and zero.

-5 is farther so it is less than -2.

7 0

2 years ago

Read 2 more answers