The probability that more than 5 students will pass their exam is 0.0188416.
<h3>How to find the probability?</h3>
The probability that a student passes their examination = 40% = 0.4
The probability that more than 5 students pass their statistics exam = Probability that 6 students pass their exam + Probability that 7 students pass their exam
The probability that 6 students pass their exam =
The probability that 7 students pass their exam =
The probability that more than 5 students pass their statistics exam = 0.0172032 + 0.0016384
= 0.0188416
Therefore, we have found the probability that more than 5 students will pass their exam to be 0.0188416.
Learn more about probability here: brainly.com/question/24756209
#SPJ4
Since we know the side length of the square (6), we can calculate its diagonal using pythagoras.
diag d = √(6²+6²) = 6√2 in
The diagonal is also the diameter of the circle! So the radius of the circle is half of that:
radius r = d/2 = 3√2 in
The area of the circle is πr² = π(3√2)² = 18π in²
To solve for , we need to isolate it on one side of the equation.
The most important part of this is knowing that whatever we do to one side of the equation, we must also do to the other.
Subtract 32 from both sides of the equation.
Divide both sides of the equation by .
Answer:
Kindly check explanation
Step-by-step explanation:
Given the data :
Technician __Shutdown
Taylor, T___4
Rousche, R _ 3
Hurley, H__ 3
Huang, Hu___2
Gupta, ___ 5
The Numbe of samples of 2 possible from the 5 technicians :
We use combination :
nCr = n! ÷ (n-r)!r!
5C2 = 5!(3!)2!
5C2 = (5*4)/2 = 10
POSSIBLE COMBINATIONS :
TR, TH, THu, TG, RH, RHu, RG , HHu, HG, HuG
Sample means :
TR = (4+3)/2 = 3.5
TH = (4+3)/2 = 3.5
THu = (4+2) = 6/2 = 3
TG = (4 + 5) = 9/2 = 4.5
RH = (3+3) = 6/2 = 3
RHu = (3+2) /2 = 2.5
RG = (3 + 5) = 8/2 = 4
HHu = (3+2) = 2.5
HG = (3+5) = 8/2 = 4
HuG = (2+5) / 2 = 3.5
Mean of sample mean (3.5+3.5+3+4.5+3+2.5+4+2.5+4+3.5) / 10 = 3.4
Population mean :
(4 + 3 + 3 + 2 + 5) / 5 = 17 /5 = 3.4
Population Mean and mean of sample means are the same.
This distribution should be approximately normal.
<span><span><span><span><span><span><span><span>here ya go 14.13</span></span><span><span /></span><span><span><span><span>m</span></span></span><span><span><span>2
</span></span></span></span></span></span></span></span></span></span><span>A≈14.13m2</span>