Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
Answer:
1) 11
2) 2
3)
4)
5) -2
6)
Step-by-step explanation:
1) 2 + 3 -
=(2 × 2 )+ (3 × 4) - 5
= 4 + 12 - 5
= 11
2) 4 -2 +
= (4 × 2) - (2 × 7) + 8
= 8 - 14 +8
= 2
3) 5 - 3
= 5× - 3× + 4× + 2×
=
=
4)
=
=
5)
=
= -2
6)
=
= 2× - 2× -
=
=
Hope the working out is clear and will help you. :)
5.692 is a terminating decimal because the decimal stopped at the digit of 2.
Hope this helps!
Answer:
(7x + 5)m
Step-by-step explanation:
area = base * height = (35x2 + 46x +15) m²
base = (5x + 3)
Using algebraic division, find the height. SEE ATTACHMENT
height = (7x + 5)