Answer:
The process by which the balloon is attracted and possibly sticks to the wall is known as static electricity which is the attraction or repulsion between electric charges which are not free to move.
The wall is an insulator.
Explanation:
When a balloon is blown and tied off, and then the balloon is rubbed on the woolly object once in one direction, and the side that was rubbed against the wool is brought near a wall and then released, it is observed that the balloon is attracted to and sticks to the wall. The above observation is due to static electricity.
Static electricity refers to electric charges that are not free to move or that are static. One of the means of generating such charges is by friction. When the balloon is rubbed on the woollen material, electrons are given away to the balloon's surface. Since the balloon is an insulator (materials which do not allow electricity to pass through them easily), the electrons are not free to move. When the balloon is brought near to a wall, there is a rearrangement of the charges present on the wall. Negative charges on the wall move farther away while the positive charges on the wall are attracted to the electrons on the balloon's surface. Because the wall is also an insulator, the charges are not discharged immediately. Therefore, this attraction between opposite charges as well as the static nature of the charges results in the balloon sticking to the wall.
To solve the problem it is necessary to apply the equations related to the Poiseuilles laminar flow law, with which the stationary laminar flow ΦV of an incompressible and uniformly viscous liquid (also called Newtonian fluid) can be determined through a cylindrical tube of constant circular section. Mathematically this can be expressed:
Where:
are the viscosities of the concrete before and after the increase
l = Length of the vessel
= Radio of the vessel before and after the increase
= Change in the pressure
The rates of flow before and after he increase
Our values are given as:
10 times her resting rate
95% of its normal value
Increase of 50%
Plugging known information to get
Therefore the factor of average radio of her blood vessels increased is 1.589 the initial factor after the increase.
Answer:
Explanation:
From the question we are told that:
Height
Radius
Height of water
Gravity
Density of water
Generally the equation for Volume of water is mathematically given by
Where
y is a random height taken to define dv
Generally the equation for Work done to pump water is mathematically given by
Substituting dv
Therefore
'
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<span>If Jack is filing married-filing-separate he would report $76,000 gross income as head of household.</span>
Answer:
2π/[28 x (10^-3)]
Explanation:
Angular speed : ω=2π/T
T = 28ms = 28 x (10^-3) s
Angular speed = 2π/[28 x (10^-3)]