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2 years ago

EXERCISE 3.4

Mathematics

1 answer:

Lisa [10]2 years ago

7 0

Answer:

I think it's C. sjisebd ddhisuaja. usually get ebe.

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Determine the domain and the range of the graph.

dimulka [17.4K]

Answer:

Domain: (-∞,∞)

Range: -1

Step-by-step explanation:

Domain means the x-coordinates covered:

(-∞,∞)

Range means the y-coordinates covered:

Only -1 because there are no other existing y-coordinates.

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2 years ago

2. Describe the transformation of the graph of f(x) = 6* that yields the graph of f(x) = 6*+1

avanturin [10]

Answer: Translation

The difference between the first equation and the second is that the second is moved one space higher. All of its points will be a unit higher than the other. Because of this change in height, the name of the transformation is a translation

Hope this helps comment below for more questions :)

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2 years ago

The amount of gas that a helicopter uses is directly proportional to the number of hours spent flying. the helicopter flies for

Anna007 [38]

3232 gallons of fuel are used up

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3 years ago

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What is the value of the expression –40 – (–50 – 2) + 10?<br><br><br> Plz help

Dafna1 [17]

The answer is 22 I looked it up to make sure i was right

7 0

2 years ago

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

8 0

2 years ago

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