Since there is no repetition allowed, there are 10 possibilities for the 1st digit, 9 for the 2nd, 8 for the 3rd, and 7 for the 4th. This gives a total of (10)(9)(8)(7) = 5040 four-digit codes.
For all odd digits to be used, there are 5 possibilities for the 1st digit (1,3,5,7,9), 4 for the 2nd, 3 for the 3rd, 2 for the 4th. This gives a total of (5)(4)(3)(2) = 120 codes that only use odd digits.
Therefore there are 5040 - 120 = 4920 codes that do not consist of all odd digits. The probability is 4920/5040 = 41/42.
Answer:
- By Double splitting method
=> 2x²-7x+5
=> 2x²-2x-5x+5
=>2x(x-1)-5(x-1)
<h2>=>(2x-5)(x-1)</h2>
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Answer:
30%
Step-by-step explanation:
Meagan completed 14/20 math problems. 14÷20 is 0.7
So she completed 70% of those math problems. The question is How many does she have left?
So she has 30% left to complete.
Answer:
E:
Step-by-step explanation:
The equation of circles is
(x-a)²+(y-b)²=r²
Where
Center = (a,b) = (-6,-3) and r = 12
Now
The equation becomes
(x+6)²+(x+3)²=144
