Answer:
im sorry for being mean goodbye im get the real answer
Explanation:
Answer:
The answer to your question is 1.013 Kg
Explanation:
TiCl₄ + 2Mg ⇒ 2MgCl₂ + Ti
mass of Mg = ?
mass of Ti = 1 kg
Process
1.- Calculate the molar mass of Magnesium and titanium (IV)
Mg = 24.3 g x 2 = 48.6 g
Ti = 48 g
2.- Write a proportion (rule of three)
48.6 g of Mg ------------- 48 g of Ti
x ------------- 1000 g of Ti
x = (1000 x 48.6) / 48
3.- Result
mass of Magnesium = 1012.5g
= 1.013 kg
I believe the correct answer is <span>that it emphasizes the curious tone of the speaker.
The speaker is interested in what is going on on that urn, what is depicted there and why. He wants to have answers to many of his questions because he is curious, and this is why he is constantly repeating the interrogative word what.
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Answer:
The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa
Explanation:
<u>Step 1</u>: Calculate the volume of a spherical container V
V = (4π*r³)/3
r = (3V/4π)^1/3
2r = d = 2*(3V/4π)^1/3
with r= radius
with d= diameter
The diameter is:
d= 2*(3V/4π)^1/3
d= 2*(3*100cm³/4π)^1/3
d= 5.76 cm
<u>Step2 </u>: Define the free path lambda λ of argon
with λ =k*T/ σp
with p = kT/σλ
with T= temperature = 20°C = 293.15 Kelvin
with k = Boltzmann's constant = 1.381 * 10^-23 J/K
with p = the atmospheric pressure
with σ = 0.36 nm²
p = kT/σλ
p = (1.38 * 10^-23 J*K^-1 * 1Pa *m³/1J)*(293,15K) /(0.36 nm²*(10^-9/ 1nm)² *(5.76cm* 10^-2m/1cm)
p = 0.195 Pa
The mean free path of argon molecules becomes comparable to the diameter of this container at a pressure of 0.195 Pa
