Answer:
lowest frequency = 535.93 Hz
distance between adjacent anti nodes is 4.25 cm
Explanation:
given data
length L = 32 cm = 0.32 m
to find out
frequency and distance between adjacent anti nodes
solution
we consider here speed of sound through air at room temperature 20 degree is approximately v = 343 m/s
so
lowest frequency will be = ..............1
put here value in equation 1
lowest frequency will be =
lowest frequency = 535.93 Hz
and
we have given highest frequency f = 4000Hz
so
wavelength = ..............2
put here value
wavelength =
wavelength = 0.08575 m
so distance = ..............3
distance =
distance = 0.0425 m
so distance between adjacent anti nodes is 4.25 cm
Roughly 13.8 billion years old according to science
The acceleration of an object depends directly upon the net force acting upon the object, and inversely upon the mass of the object. As the force acting upon an object is increased, the acceleration of the object is increased. As the mass of an object is increased, the acceleration of the object is decreased.
|Acceleration| = (change in speed) / (time for the change).
Change in speed = (6 mi/hr - 25 mi/hr) = -19 mi/hr
Time for the change = 10 sec
|Acceleration| = (-19 mi/hr) / (10 sec) = -1.9 mile per hour per second
Admittedly, that's a rather weird unit.
Other units, perhaps more comfortable ones, are:
-6,840 mi/hr²
-2.79 feet/sec²
Answer:
Regions near rivers have water surfaces that rapidly change in temperature from cold to hot.
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