Helppppppppppp please

Mathematics

1 answer:

zheka24 [161]2 years ago

8 0

Answer:

130 degrees

Step-by-step explanation:

when an angle is in a circle it equals the same degrees as the curve in front of it except you divide by 2. So if the curve ARC is 100 degrees and a circle is 360 degrees,

360-100= 260

260/2 = 130

hope i helped!

You might be interested in

Jamie has $30 in a savings account. The interest rate is 10% per year and is not

erastova [34]

Answer:

the answer is 30 * 0.10 * 3

Step-by-step explanation:

the equation is money * interest * time

8 0

2 years ago

HELPPPPPPPPPPPPPPPPPPPPPPP

amid [387]

I DONT KNOW BUT THAT'S MY ANSWER HOPE IT HELP

6 0

2 years ago

Read 2 more answers

Solve for r and t:<br> 6r - 3t = 6<br> 6r + 8t = -16

MAVERICK [17]

Multiply the first equation with (-1)
you should get this

-6r + 3t = -6
6r + 8t = -16

start to eliminate

11t = -22

divide by 11

t = -2

substitute

6r - 3(-2) = 6
6r + 6 = 6
6r = 6 - 6
6r = 0
r=0

8 0

2 years ago

If f(x) and its inverse function, f^-1(x), are both plotted on the same coordinate plane, what is their point of intersection?

Romashka-Z-Leto [24]

Answer:

(a, a)

Step-by-step explanation:

actually there are two cases, don't have intersection and have. if have intersection, then they intersect at line y = x or point (a, a) by definition of inverse function.

8 0

2 years ago

Read 2 more answers

What are the vertical asymptotes of the function f(x) =5x+5/x2 + x-2

katen-ka-za [31]

let's recall that the vertical asymptotes for a rational expression occur when the denominator is at 0, so let's zero out this one and check.

$\bf \cfrac{5x+5}{x^2+x-2}\qquad \stackrel{\textit{zeroing out the denominator}~\hfill }{x^2+x-2=0\implies (x+2)(x-1)=0}\implies \stackrel{\textit{vertical asymptotes}}{ \begin{cases} x=-2\\ x=1 \end{cases}}$

5 0

2 years ago