In scientific terms, ultrasound is a sound pressure, cyclic in nature, that has a greater frequency than the limit at the top of human hearing capabilities. What this means is that an ultrasonic sound can’t be heard by the human ear because their frequency is too high for our ears to pick up. In healthy young adults, this upper hearing capability is an average of 20 kilohertz. Ultrasound has many applications in several fields. Perhaps the best known application for ultrasound is sonography. This is where medical staff use the high pitched noise to produce a picture of a fetus while in the mother’s womb. Another use however, doesn’t directly concern humans at all. Bats use the high pitched noises to see in the dark and get an accurate reading on their preys internal structure. A popular belief is that an ultrasonic sound has the ability to turn the locking mechanism in a door lock, as demonstrated on some spy movies. On the opposite side of this are infrasonic sounds. These are noises with a frequency less than the lowest level of human hearing capabilities is 20 hertz. It is possible for humans to perceive infrasonic sounds, but only if the air pressure is sufficient. Although the war is the main tool for hearing these low sounds, it is possible for other parts of the body to “feel them”. Infrasound can be used to send signals in the army to special machines that can pick them up. These can be used to transmit vital data. Animals are able to pick up some low infrasonic noises which warn them of natural disasters before they happen, generally earthquakes and tsunamis.
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One possible unit is liter, which is a basic unit in metric system. 1 liter=10 cm^3, or 0.001 m^3, so we also know that other possible units include cubic centimeters or cubic meters, which are derived units, since they are derived from basic unit, meter, representing the length, breadth, and height of the cuboid.
The wavelength will remain unchanged.
Explanation:
The velocity of a wave in terms of its wavelength and frequency is
(1)
so if we double both the velocity and the frequency, the equation above becomes
(2)
Solving for the wavelength from Eqn(2), we get
We would have gotten the same result had we used Eqn(1) instead.
Answer:
Explanation:
The distance traveled by the sound wave between the beats of the wing is its wavelength, since it is defined as the distance traveled by a periodic disturbance that propagates in a cycle, is defined as:
Where v is the speed of sound and f the frequency of the wing beats