Answer:
600 mg
Explanation:
The initial amount of the drug = 200 mg
The half-life of the drug = 8 hrs
It means that:-
After 6 hours, the concentration becomes :- mg
After 12 hours, the concentration becomes :- mg
After 18 hours, the concentration becomes :- mg
And so on...
Thus,
After infinite time =
Thus,
After infinite time =
The sum of the infinite series is:- =
So,
<u>After infinite time = mg = 600 mg</u>
Answer
is: The molar solubility of calcium phosphate is 108s⁵ = Ksp.
<span>
Balanced chemical reaction: Ca</span>₃(PO₄)₂(s) → 3Ca²⁺(aq) + 2PO₄³⁻(aq).<span>
[Ca²</span>⁺] =
3s(Ca₃(PO₄)₂) =
3s.<span>
[PO</span>₄³⁻] = 2s.<span>
Ksp = [Ca²</span>⁺]³ · [PO₄³⁻]².<span>
Ksp = (3s)³ · (2s)².
Ksp = 108s</span>⁵.
s = ⁵√(Ksp ÷ 108).
Monosaccharides are the simplest carbohydrates. Although glucose and fructose have the same molecular formula they have different structures or the atoms are arranged differently from each other and this is evident in the way they react, behave and in their properties.
Both of them are a hope this helps
Answer : The energy of the photon emitted is, -12.1 eV
Explanation :
First we have to calculate the orbit of hydrogen atom.
Formula used :
where,
= energy of orbit
n = number of orbit
Z = atomic number of hydrogen atom = 1
Energy of n = 1 in an hydrogen atom:
Energy of n = 2 in an hydrogen atom:
Energy change transition from n = 1 to n = 3 occurs.
Let energy change be E.
The negative sign indicates that energy of the photon emitted.
Thus, the energy of the photon emitted is, -12.1 eV