2 years ago

What unbalanced force is required to accelerate a 1500 kg race car at 3.00 m/s/s?

1 answer:

4 0

Answer:166.66

Step by step explanation

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Tom [10]

You need to first set up the equation:

It would look like 90 divided by 360 multiplied by the given circumference which is 72 cm.

So 90 / 360 x 72

Simply the fraction above, it will give us:

¼ x 72

So the answer would be 18 cm that is the length of DE (minor arc)

4 0

3 years ago

Dima020 [189]

Answer:

Step-by-step explanation:

7 0

2 years ago

Evgen [1.6K]

1.500 since 45 rounds to 50

8 0

2 years ago

nalin [4]

Total weight=number of pennies times weight of 1 penny
total weight/weight of 1 penny=number of pennies
636.3/3.03=210

210 pennies

8 0

2 years ago

ahrayia [7]

Answer: $100,000$

Step-by-step explanation:

Given :

$logx - 2 = 3$

add 2 to both sides

$log x = 5$

Therefore :

$x = 10^{5}$

$x = 100,000$

4 0

2 years ago