The expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
From the question,
We are to factorize the expression (h+2k)²+4k²-h² completely
The expression can be factorized as shown below
(h+2k)²+4k²-h² becomes
(h+2k)² + 2²k²-h²
(h+2k)² + (2k)²-h²
Using difference of two squares
The expression (2k)²-h² = (2k+h)(2k-h)
Then,
(h+2k)² + (2k)²-h² becomes
(h+2k)² + (2k +h)(2k-h)
This can be written as
(h+2k)² + (h +2k)(2k-h)
Now,
Factorizing, we get
(h +2k)[(h+2k) + (2k-h)]
Hence, the expression factorized completely is (h +2k)[(h+2k) + (2k-h)]
Learn more here:brainly.com/question/12486387
Step-by-step explanation:
<u>y</u> - <u>4</u> = -4
x - 6
y - 4 = -4x + 24
y = -4x + 24 + 4
y = -4x + 28
Answer:
yes
Step-by-step explanation:
Answer: 5-10g+20h
Step-by-step explanation:
You can rewrite as 5(1-2g+4h). 5x1 equals 5, 5x2g=10g, 5x4h=20h, then you get 5-10g+20h
-viridiancat4, an 8th grader! :)
