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2 years ago

5

If you are given the surface area of a square pyramid and the area of the base, how could you calculate the area of each side of

the pyramid?

1 answer:

stiv31 [10]2 years ago

8 0

Answer:

you need to divide the surface are and the base and you should get the number of each lateral face

Step-by-step explanation:

but you do need to tell me the numbers so do that in the comments

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Edgar wants to plot the ordered pair (1.8, -1.2) on a coordinate plane. On each axis, one grid square equals 0.1. starting at th

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Edgar can count 18 units right and count down 12

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3 years ago

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Whats 9*20(10+20) First Answer Gets Brainliest

Tcecarenko [31]

Answer:

Your answer would be 5400.

Step-by-step explanation:

You have to follow PEMDAS for this one. You will start within the parenthesis and add 10 and 20 together to get 30. You would then times that by 20 and get 600. Finally, you would mulitply that by 9 and get 5400 as your answer..

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2 years ago

Kyle was playing a new video game.He scored 128 points on his first game.He scored 305 points on his second game,and 490 on his

Ivahew [28]

First game= 128
Second game= 305
Third game= 490

Add the points per game together.

= 128 + 305 + 490
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5 0

2 years ago

Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

<u>Step-by-step explanation:</u>

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

<u>The Quadratic Formula:</u> For $a x^{2}+b x+c=0$ , the values of x which are the solutions of the equation are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Where, a = 1, b = 3 and c = -10

$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

$x=\frac{-3+7}{2}=\frac{4}{2}=2$

$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

The solutions for ‘x’ are 2 and -5

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2 years ago

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260 weeks equal how many years

sattari [20]

5 years equals 260 weeks

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3 years ago

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