Step-by-step explanation:
yes that's true
if a^n=b
then
a^n/n=b^1/n
a=b^1/n
You multiply both of the equations until you have two of the same term the same like for example, say I have 4x and 5x. You want to multiply until both have the same number, so multiply 5x by four, then multiply 4x by five, and you will get 20x, then both of those cancel out and you will be left with the other variable, and you just solve like a normal equation.
Answer:
The amount that would be in the account after 30 years is $368,353
Step-by-step explanation:
Here, we want to calculate the amount that will be present in the account after 30 years if the interest is compounded yearly
We proceed to use the formula below;
A = [P(1 + r)^t-1]/r
From the question;
P is the amount deposited yearly which is $4,500
r is the interest rate = 2.5% = 2.5/100 = 0.025
t is the number of years which is 30
Substituting these values into the equation, we have;
A = [4500(1 + 0.025)^30-1]/0.025
A = [4500(1.025)^29]/0.025
A = 368,353.3309607034
To the nearest whole dollars, this is;
$368,353
Answer:
The choice three ;
Step-by-step explanation: