I think the answer is B.
If that's not it, then it must be A.
Suppose you add x liters of pure water to the 10 L of 25% acid solution. The new solution's volume is x + 10 L. Each L of pure water contributes no acid, while the starting solution contains 2.5 L of acid. So in the new solution, you end up with a concentration of (2.5 L)/(x + 10 L), and you want this concentration to be 10%. So we have
and so you would need to add 15 L of pure water to get the desired concentration of acid.
Answer:
x=2√5/5
x=-2√5/5
Step-by-step explanation:
13√(2√5/5)^2-(2√5/5)^4+9√(2√5/5)^2+(2√5/5)^4=16
13√(4×5/25)-(16×25/625)+9√(4×5/25)+(16×25/625)
13√(4/5)-(16/25)+9√(4/5)+(16/25)
13√(4/25)+9√(36/25)
13×2/5+9×6/5
26/5+54/5
16=16 (proven)
Answer:
Steve
Step-by-step explanation:
steve is buying 200 minutes which is more than 150 minutes
Hope i helped :) :) :)